Рефакторинг: Вынес restorePath() в отдельный общий файл

MusinAA/task2/strategyObjects/BFS.py

@@ -1,4 +1,5 @@
 from task2.strategyObjects.pathFindingStrategy import PathFindingStrategy
+from task2.strategyObjects.util import restorePath
 
 from task2.mazeObjects.maze import Maze
 from task2.mazeObjects.cell import Cell
@@ -6,7 +7,8 @@ from task2.mazeObjects.cell import Cell
 import queue
 
 class BFS(PathFindingStrategy):
-    """Поиск в ширину – гарантирует кратчайший путь по количеству шагов."""
+    """Поиск в ширину – гарантирует кратчайший путь по количеству шагов.
+    Возвращает None, если пути нет"""
     def findPath(self, maze: Maze, start: Cell, exit: Cell):
         visited = dict()
         parents = dict()
@@ -29,14 +31,4 @@ class BFS(PathFindingStrategy):
                 visited[hood] = visited[current] + 1
                 parents[hood] = current
                 q.put(hood)
-        return self.restorePath(parents, start, exit)
+        return restorePath(parents, start, exit)
-
-    def restorePath(self, parents: dict, start: Cell, exit: Cell) -> list[Cell]|None:
-        path = []
-        current = exit
-        while current:
-            path.append(current)
-            if current not in parents:
-                return []
-            current = parents[current]
-        return path[::-1]

MusinAA/task2/strategyObjects/DFS.py

@@ -1,9 +1,34 @@
 from task2.strategyObjects.pathFindingStrategy import PathFindingStrategy
+from task2.strategyObjects.util import restorePath
 
 from task2.mazeObjects.maze import Maze
 from task2.mazeObjects.cell import Cell
 
+
 class DFS(PathFindingStrategy):
-    """Поиск в глубину – быстрый, но не обязательно кратчайший."""
+    """Поиск в глубину – быстрый, но не обязательно кратчайший.
+    Возвращает None, если пути нет"""
     def findPath(self, maze: Maze, start: Cell, exit: Cell):
-        ...
+        visited = dict()
+        parents = dict()
+        stack = []
+
+        stack.append(start)
+        visited[start] = 0
+        parents[start] = None
+
+        while stack:
+            current = stack.pop()
+
+            # Условие нахождение выхода
+            if current == exit: break
+
+            # Перебор соседей
+            for hood in maze.getNeighbors(current):
+                if hood in visited:
+                    continue
+                visited[hood] = visited[current] + 1
+                parents[hood] = current
+                stack.append(hood)
+        
+        return restorePath(parents, start, exit)

MusinAA/task2/strategyObjects/util.py

@@ -0,0 +1,12 @@
+from task2.mazeObjects.maze import Maze
+from task2.mazeObjects.cell import Cell
+
+def restorePath(parents: dict, start: Cell, exit: Cell) -> list[Cell]|None:
+    path = []
+    current = exit
+    while current:
+        path.append(current)
+        if current not in parents:
+            return None
+        current = parents[current]
+    return path[::-1]